Question: The mean of four positive integers is 5 . the median of the four integers is 6 . what is the mean of the largest and smallest of the integers?
Answer: Let say four numbers are A , B , C , D arranged in ascending order
A – Smallest
D – Largest
Mean = (A + B + C + D)/4
=> 5 = (A + B + C + D)/4
=> A + B + C + D = 20
Median = ( B + C)/2
=> 6 = (B + C)/2
=> B + C = 12
=> A + 12 + D = 20
=> A + D = 8
=> (A + D)/2 = 4
mean of the largest and smallest of the integers = 4
Few example Satisfying all these : ( for understanding)
1 6 6 7
1 5 7 7
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